A) \[{{x}^{2}}+{{y}^{2}}-6x-5y+9=0\]
B) \[{{x}^{2}}+{{y}^{2}}+6x+5y-9=0\]
C) \[{{x}^{2}}+{{y}^{2}}-6x+5y-9=0\]
D) \[{{x}^{2}}+{{y}^{2}}+6x-5y+9=0\]
Correct Answer: A
Solution :
\[{{k}^{2}}=4+{{(k-4)}^{2}}\Rightarrow k=\frac{5}{2}\] Hence required equation of circle is \[{{(x-3)}^{2}}+{{\left( y-\frac{5}{2} \right)}^{2}}={{\left( \frac{5}{2} \right)}^{2}}\Rightarrow {{x}^{2}}+{{y}^{2}}-6x-5y+9=0\] Trick: Only (a) passes through (1, 4).You need to login to perform this action.
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