A) \[{{x}^{2}}+{{y}^{2}}+4x=0\]
B) \[{{x}^{2}}+{{y}^{2}}-8y=0\]
C) \[{{x}^{2}}+{{y}^{2}}\pm 8x=0\]
D) \[{{x}^{2}}+{{y}^{2}}+8y=0\]
Correct Answer: C
Solution :
As the centre may be \[(\pm 4,\ 0)\] and radius = 4.
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