JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
    The equation of  the circle whose diameters have the end points (a, 0) (0, b) is given by                           [MP PET 1993]

    A)            \[{{x}^{2}}+{{y}^{2}}-ax-by=0\]                                    

    B)            \[{{x}^{2}}+{{y}^{2}}+ax-by=0\]

    C)            \[{{x}^{2}}+{{y}^{2}}-ax+by=0\]                                  

    D)            \[{{x}^{2}}+{{y}^{2}}+ax+by=0\]

    Correct Answer: A

    Solution :

               Required equation is \[(x-a)x+(y-b)y=0\] or \[{{x}^{2}}-ax+{{y}^{2}}-by=0\].


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