question_answer

A circle which passes through origin and cuts intercepts on axes a and b, the equation of circle is            [RPET 1991]

A)                                                                      \[{{x}^{2}}+{{y}^{2}}-ax-by=0\]                                    

B)            \[{{x}^{2}}+{{y}^{2}}+ax+by=0\]

C)            \[{{x}^{2}}+{{y}^{2}}-ax+by=0\]                                  

D)            \[{{x}^{2}}+{{y}^{2}}+ax-by=0\]

Correct Answer: A

Solution :

           Centre is \[\left( \frac{a}{2},\ \frac{b}{2} \right)\] and radius \[=\sqrt{\frac{{{a}^{2}}+{{b}^{2}}}{4}}\]