A) \[{{l}_{1}}{{l}_{2}}={{m}_{1}}{{m}_{2}}\]
B) \[{{l}_{1}}{{m}_{1}}={{l}_{2}}{{m}_{2}}\]
C) \[{{l}_{1}}{{l}_{2}}+{{m}_{1}}{{m}_{2}}=0\]
D) \[{{l}_{1}}{{m}_{2}}={{l}_{2}}{{m}_{1}}\]
Correct Answer: A
Solution :
\[{{P}_{1}}\equiv \left( -\frac{{{n}_{1}}}{{{l}_{1}}},\ 0 \right)\],\[{{P}_{2}}\equiv \left( 0,\ \frac{-{{n}_{1}}}{{{m}_{1}}} \right)\],\[{{P}_{3}}\equiv \left( -\frac{{{n}_{2}}}{{{l}_{2}}},\ 0 \right)\] and \[{{P}_{4}}\equiv \left( 0,\ -\frac{{{n}_{2}}}{{{m}_{2}}} \right)\] \[\{\angle {{P}_{1}}{{P}_{2}}{{P}_{3}}=\angle {{P}_{1}}{{P}_{4}}{{P}_{3}}\}\]You need to login to perform this action.
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