A) \[{{x}^{2}}+{{y}^{2}}-4x-4y+16=0\]
B) \[{{x}^{2}}+{{y}^{2}}-8x-8y+16=0\]
C) \[{{x}^{2}}+{{y}^{2}}+4x+4y+4=0\]
D) \[{{x}^{2}}+{{y}^{2}}-4x-4y+4=0\]
Correct Answer: D
Solution :
\[{{(x-2)}^{2}}+{{(y-2)}^{2}}=4\] \[{{x}^{2}}+4-4x+{{y}^{2}}+4-4y=4\] \[{{x}^{2}}+{{y}^{2}}-4x-4y+4=0\].You need to login to perform this action.
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