JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
    Locus of the points from which perpendicular tangent can be drawn to the circle \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\], is

    A)            A circle passing through origin

    B)            A circle of radius 2a

    C)            A concentric circle of radius \[a\sqrt{2}\]

    D)            None of these

    Correct Answer: C

    Solution :

               Required locus is \[S{{S}_{1}}={{T}^{2}}\]                    \[({{x}^{2}}+{{y}^{2}}-{{a}^{2}})({{h}^{2}}+{{k}^{2}}-{{a}^{2}})={{(hx+ky-{{a}^{2}})}^{2}}\]                    But as given, coefficient of \[{{x}^{2}}+\] coefficient of \[{{y}^{2}}=0\]                    \[\Rightarrow \]\[{{h}^{2}}+{{k}^{2}}=2{{a}^{2}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner