JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Equilibrium of Forces

  • question_answer
    The resultant of two forces \[3P\] and \[2P\]is R. If the first force is doubled then the resultant is also doubled. The angle between the two forces is            [KCET 2001]

    A)             \[{{60}^{\text{o}}}\]          

    B)           \[{{120}^{o}}\]

    C)             \[{{70}^{o}}\]         

    D)             \[{{180}^{o}}\]

    Correct Answer: B

    Solution :

                    \[{{R}^{2}}={{(3P)}^{2}}+{{(2P)}^{2}}+2\times 3P\times 2P\times \cos \theta \]  ?(i)             \[{{(2R)}^{2}}={{(6P)}^{2}}+{{(2P)}^{2}}+2\times 6P\times 2P\times \cos \theta \]          ?(ii)             by solving (i) and (ii), \[\cos \theta =-1/2\] Þ \[\theta =120{}^\circ \]


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