A) (2.00 ± 0.01) s
B) (2.00 +0.025) s
C) (2.00 ± 0.05) s
D) (2.00 ± 0.10) s
Correct Answer: C
Solution :
Mean time period T = 2.00 sec & Mean absolute error \[=\Delta T\]= 0.05 sec. To express maximum estimate of error, the time period should be written as \[(2.00\pm 0.05)\]secYou need to login to perform this action.
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