NEET Physics Mathematical Tools, Units & Dimensions Question Bank Errors of Measurement

  • question_answer
    The radius of a sphere is (5.3 ± 0.1) cm. The percentage error in its volume is 

    A)          \[\frac{0.1}{5.3}\times 100\]

    B)                                        \[3\times \frac{0.1}{5.3}\times 100\]            

    C)          \[\frac{0.1\times 100}{3.53}\]

    D)          \[3+\frac{0.1}{5.3}\times 100\]

    Correct Answer: B

    Solution :

                 \[\because V=\frac{4}{3}\pi {{r}^{3}}\]               \ % error in volume               \[=3\times %\] error in radius.          \[=\frac{3\times 0.1}{5.3}\times 100\]


You need to login to perform this action.
You will be redirected in 3 sec spinner