NEET Physics Mathematical Tools, Units & Dimensions Question Bank Errors of Measurement

  • question_answer
    The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00\[\pm 0.05\]) Newton and weight in water is (4.00\[\pm \]0.05) Newton. Then the relative density along with the maximum permissible percentage error is   

    A)            5.0 \[\pm \]11%

    B)                                      5.0 \[\pm \]1%

    C)            5.0 \[\pm \]6%

    D)                                      1.25 \[\pm \]5%

    Correct Answer: A

    Solution :

               Weight in air \[=(5.00\pm 0.05)\,N\]               Weight in water\[=(4.00\pm 0.05)\,N\]               Loss of weight in water \[=(1.00\pm 0.1)\,N\]               Now relative density \[=\frac{\text{weight}\,\text{in}\,\text{air }}{\text{weight }\text{loss in water}}\]                i.e. R . D\[=\frac{5.00\pm 0.05}{1.00\pm 0.1}\]               Now relative density with max permissible error               \[=\frac{5.00}{1.00}\pm \left( \frac{0.05}{5.00}+\frac{0.1}{1.00} \right)\times 100\]\[=5.0\pm (1+10)%\] \[=5.0\pm 11%\]


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