A) 0.1%
B) 1%
C) 0.2%
D) 0.8%
Correct Answer: C
Solution :
\[T=2\pi \sqrt{l/g}\] \[\Rightarrow {{T}^{2}}=4{{\pi }^{2}}l/g\] \[\Rightarrow g=\frac{4{{\pi }^{2}}l}{{{T}^{2}}}\] Here % error in l = \[\frac{1mm}{100cm}\times 100=\frac{0.1}{100}\times 100=0.1%\] and % error in T =\[\frac{0.1}{2\times 100}\times 100=0.05%\] \ % error in g = % error in l + 2(% error in T) \[=0.1+2\times 0.05\]= 0.2 %You need to login to perform this action.
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