A) 1
B) 3
C) 5
D) ?1
Correct Answer: B
Solution :
\[xdy=y(dx+ydy)\] Þ \[\frac{xdy-ydx}{{{y}^{2}}}=dy\] Þ \[-d\left( \frac{x}{y} \right)=dy\] Integrating both sides, we get \[\frac{x}{y}+y=c\] \[\because \]\[y(1)=1\Rightarrow \,c=2\]; \[\therefore \]\[\frac{x}{y}+y=2\] For \[x=-3\], \[{{y}^{2}}-2y-3=0\Rightarrow y=-1\] or 3 \[\Rightarrow y=3\] \[(\because \,\,y>0)\]You need to login to perform this action.
You will be redirected in
3 sec