A) \[a(x+y+z)+b(p+q+r)+c\]
B) 0
C) \[abc+xyz+pqr\]
D) None of these
Correct Answer: B
Solution :
\[\left| \,\begin{matrix} a-b & b-c & c-a \\ x-y & y-z & z-x \\ p-q & q-r & r-p \\ \end{matrix}\, \right|=\left| \,\begin{matrix} 0 & b-c & c-a \\ 0 & y-z & z-x \\ 0 & q-r & r-p \\ \end{matrix}\, \right|\] = 0 [by \[{{C}_{1}}\to {{C}_{1}}+{{C}_{2}}+{{C}_{3}}]\]
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