A) - 440
B) 0
C) 328
D) 488
Correct Answer: B
Solution :
\[\left| \,\begin{matrix} 2 & 8 & 4 \\ -5 & 6 & -10 \\ 1 & 7 & 2 \\ \end{matrix}\, \right|\,=2\,\left| \,\begin{matrix} 2 & 8 & 2 \\ -5 & 6 & -5 \\ 1 & 7 & 1 \\ \end{matrix}\, \right|=0\] (Taking 2 common from\[{{C}_{3}}\]).You need to login to perform this action.
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