A) \[{D}'=D\]
B) \[{D}'=D(1-pqr)\]
C) \[{D}'=D(1+p+q+r)\]
D) \[{D}'=D(1+pqr)\]
Correct Answer: D
Solution :
\[{D}'=D+pqr\,D=D(1+pqr)\]. Trick: Check by putting \[B=I\] and all other zero.You need to login to perform this action.
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