A) 16
B) 18
C) 17
D) 19
Correct Answer: B
Solution :
Since it is an identity in \[\left| \,\begin{matrix} a(1+w) & b{{w}^{2}} & aw \\ b(w+{{w}^{2}}) & c & b{{w}^{2}} \\ c({{w}^{2}}+1) & aw & c \\ \end{matrix}\, \right|\] so satisfied by every value of \[\lambda \]. Now put \[BC=[-b\,\,-a]\,\left[ \begin{align} & \,\,\,a \\ & -a \\ \end{align} \right]=[{{a}^{2}}-ab]\] in the given equation, we have \[t=\left| \,\begin{matrix} 0 & -1 & 3 \\ 1 & 2 & -4 \\ -3 & 4 & 0 \\ \end{matrix}\, \right|\,=-12+30=18\].You need to login to perform this action.
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