A) \[{{e}^{x}}\]
B) \[{{e}^{-x}}\]
C) \[e\]
D) \[{{e}^{{{x}^{2}}}}\]
Correct Answer: B
Solution :
\[1-x+\frac{{{x}^{2}}}{2!}-\frac{{{x}^{2}}}{3!}+....\infty ={{e}^{-x}}\].You need to login to perform this action.
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