A) 0
B) 1
C) \[-1\]
D) 2
Correct Answer: B
Solution :
\[{{\left( \frac{e+{{e}^{-1}}}{2} \right)}^{2}}-{{\left( \frac{e-{{e}^{-1}}}{2} \right)}^{2}}=\frac{1}{4}\{4\,.\,e\,.\,{{e}^{-1}}\}=1\].You need to login to perform this action.
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