A) \[\frac{1}{2}\]
B) 1
C) 0
D) None of these
Correct Answer: C
Solution :
\[\frac{{{e}^{4x}}-1}{{{e}^{2x}}}={{e}^{2x}}-{{e}^{-2x}}=2\left\{ 2x+\frac{{{(2x)}^{3}}}{3\ !}+\frac{{{(2x)}^{5}}}{5\ !}+..... \right\}\] The coefficient of\[{{x}^{2}}=0\].You need to login to perform this action.
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