A) \[{}^{81}/{}_{4}\]
B) \[{}^{5}/{}_{9}\]
C) \[\frac{9}{5}\]
D) \[\frac{4}{81}\]
Correct Answer: C
Solution :
(c) \[{{3}^{-2}}=\frac{1}{{{3}^{2}}}=\frac{1}{9},\]\[=\frac{1}{{{\left( {}^{3}/{}_{2} \right)}^{2}}}=\frac{1}{{}^{9}/{}_{4}}=\frac{4}{9}\] \[={{\left( \frac{1}{9}+\frac{4}{9} \right)}^{-1}}={{\left( \frac{5}{9} \right)}^{-1}}=\frac{9}{5}\]You need to login to perform this action.
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