A) 9
B) 10
C) 11
D) 13
Correct Answer: B
Solution :
(b) \[{{2}^{2x-y}}=32\] \[\Rightarrow 2x-y=5\] ??..(1) \[\Rightarrow {{2}^{x+y}}=16\Rightarrow x+y=4\] ??(2) Adding (1) & (2) \[\Rightarrow 3x=9\Rightarrow x=3\] \[\Rightarrow y=4-3=1\] \[\therefore {{x}^{2}}+{{y}^{2}}={{3}^{2}}+{{1}^{2}}=10\].You need to login to perform this action.
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