A) 200 times of the original
B) \[{{\text{2}}^{\text{10}}}\] times of the original
C) \[{{\text{2}}^{\text{8}}}\] times of the original
D) \[{{\text{2}}^{\text{6}}}\] times of the original
Correct Answer: C
Solution :
Let no. of cells al present be x No. of cells after \[\text{1 hour = }2x\] No. of cells after 2\[~\text{hours}=2(2x)=4x={{2}^{2}}x\] No. of cells after 3 \[\text{hours}=2(4x)=8x={{2}^{3}}x\] \[\therefore \] No. of cells after 8 hours \[={{2}^{8}}x\]
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