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7th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    Simplify  \[\frac{{{({{a}^{-n}})}^{m}}\times {{a}^{-2m}}}{{{a}^{mn}}\times {{a}^{2m}}}\].

    A)  \[{{a}^{2m(n-2)}}\]       

    B)         \[{{a}^{2m(2n-4)}}\]         

    C)  \[{{a}^{-2m(n+2)}}\]       

    D)         \[{{a}^{2m(n-4)}}\]

    Correct Answer: C

    Solution :

     \[\frac{{{({{a}^{-n}})}^{m}}\times {{a}^{-2m}}}{{{a}^{mn}}\times {{a}^{2m}}}\]\[={{a}^{-2mn-4m}}={{a}^{-2m(n+2)}}\]


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