A) \[{{a}^{2m(n-2)}}\]
B) \[{{a}^{2m(2n-4)}}\]
C) \[{{a}^{-2m(n+2)}}\]
D) \[{{a}^{2m(n-4)}}\]
Correct Answer: C
Solution :
\[\frac{{{({{a}^{-n}})}^{m}}\times {{a}^{-2m}}}{{{a}^{mn}}\times {{a}^{2m}}}\]\[={{a}^{-2mn-4m}}={{a}^{-2m(n+2)}}\]You need to login to perform this action.
You will be redirected in
3 sec