8th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    Simplify \[{{\left( \frac{{{a}^{-2}}}{{{b}^{-2}}} \right)}^{-3}}\left( \frac{{{a}^{-3}}}{{{b}^{-5}}} \right)\] 

    A)  \[\frac{1}{{{b}^{2}}}\]                      

    B)  \[\frac{{{a}^{3}}}{{{b}^{11}}}\]

    C)  \[\frac{a}{b}\]                                     

    D)  \[\frac{{{a}^{2}}}{{{b}^{3}}}\]

    Correct Answer: B

    Solution :

    (b) \[{{\left( \frac{{{a}^{-2}}}{{{b}^{-2}}} \right)}^{-3}}\times \left( \frac{{{a}^{-3}}}{{{b}^{5}}} \right)\] \[=\frac{{{a}^{+6}}}{{{b}^{+6}}}\times \frac{{{a}^{-3}}}{{{b}^{5}}}\] \[=\frac{{{a}^{3}}}{{{b}^{11}}}\].


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