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8th Class Mathematics Factorisation Question Bank Factorisation

  • question_answer
    One of the factors of (\[{{(p+q)}^{2}}-{{(a-b)}^{2}}\]\[+p+q-a+b\] is

    A)  \[(p+q+a+b)\]         

    B)  \[(p+q-a+b)\]

    C)  \[(p-q+a-b)\]

    D)         \[(p-q+a+b)\]

    Correct Answer: B

    Solution :

    We have. \[{{(p+q)}^{2}}-{{(a-b)}^{2}}+p+q-a+b\] \[=[{{(p+q)}^{2}}-{{(a-b)}^{2}}]+(p+q)-(a-b)\] \[=[\{(p+q)+(a-b)\}\{(p+q)-(a-b)\}]\]                                     \[+\{(p+q)-(a-b)\}\] \[=\{(p+q)-(a-b)\}[(p+q)+(a-b)+1]\] \[=(p+q-a+b)(p+q+a-b+1)\]


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