A) -2, 5
B) 5, 25
C) 10, 20
D) 6, 25
Correct Answer: D
Solution :
\[:{{x}^{2}}+2x+5\] be a factor of \[{{x}^{4}}+p{{x}^{2}}+q\] So, other be \[{{x}^{2}}-2x+5\] So \[({{x}^{2}}-2x+5)({{x}^{2}}+2x+5)\] \[={{({{x}^{2}}+5)}^{2}}-4{{x}^{2}}={{x}^{4}}+10{{x}^{2}}+25-4{{x}^{2}}\] \[={{x}^{4}}+6{{x}^{2}}+25\] So, \[p=6,\] \[q=25\]You need to login to perform this action.
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