A) 5 amp
B) 0.5 amp
C) 0.05 amp
D) \[5\times {{10}^{8}}\ amp\]
Correct Answer: A
Solution :
\[I=\frac{e}{R}=\frac{-N\left( d\varphi /dt \right)}{R}=\frac{10\times {{10}^{8}}\times {{10}^{-4}}\times {{10}^{-4}}\times 10}{20}\]= 5 AYou need to login to perform this action.
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