A) 0.2 C
B) 0.4 C
C) 2 C
D) 4 C
Correct Answer: B
Solution :
\[\Delta Q=\frac{NBA}{R}\left( \cos {{\theta }_{1}}-\cos {{\theta }_{2}} \right)\] \[=\frac{500\times 0.2\times 0.1\left( \cos 0-\cos 180 \right)}{50}=0.4\ C\]You need to login to perform this action.
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