A) 6.55 T
B) 5.66 T
C) 0.655 T
D) 0.566 T
Correct Answer: D
Solution :
\[q=-\frac{N}{R}\left( {{B}_{2}}-{{B}_{1}} \right)A\cos \theta \] \[32\times {{10}^{-6}}\]\[=-\frac{100}{\left( 160+40 \right)}\left( 0-B \right)\times \pi \times {{\left( 6\times {{10}^{-3}} \right)}^{2}}\times \cos {{0}^{o}}\] \[\Rightarrow B=0.565\ T\]
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