A) 48250 Faradays
B) 48250 Coulombs
C) 193000 Faradays
D) 193000 Coulombs
Correct Answer: B
Solution :
Electricity required = No. of gm equivalent ´ 96500 coulombs = 0.5 ´ 96500 = 48250 C.You need to login to perform this action.
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