JEE Main & Advanced
Chemistry
Electrochemistry / विद्युत् रसायन
Question Bank
Faraday's law of electrolysis
question_answer
2.5 F of electricity are passed through a \[CuS{{O}_{4}}\] solution. The number of gm equivalent of Cu deposited on anode is [CPMT 1973; DPMT 1982; MP PMT 2001]
A) Zero
B) 1.25
C) 2.5
D) 5.0
Correct Answer:
C
Solution :
\[\because \] 1F obtained from 1 g equivalent \[\therefore \,\] 2.5 F obtained from 2.5 g equivalent.