A) 23
B) 32
C) 12
D) 20
Correct Answer: B
Solution :
In 5 gm CuO, 4 gm Cu and 1 gm O be present.Element | Wt. | At Wt. | \[Wt./At.Wt.\ne x\] | Ratio |
Cu | 4 gm | 63.5 | 4/63.5=.0625 | \[\frac{.0625}{.0625}=1\] |
O | 1 gm | 16 | 1/16 =.0625 | \[\frac{.0625}{.0625}=1\] |
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