JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    A current 2.0 A is passed for 5 hours through a molten metal salt deposits 22 g of metal (At. wt. =177). The oxidation state of the metal in the metal salt is      [KCET 1996]

    A)                 + 1         

    B)                 + 2

    C)                 + 3         

    D)                 + 4

    Correct Answer: C

    Solution :

               \[{{E}_{\text{metal}}}=\frac{\text{Weight}\,\,\text{of}\,\text{metal}\times 96500}{\text{N}\text{umber}\,\text{of}\,\text{coulombs}}\]            \[=\frac{22.2\times 96500}{2\times 5\times 60\times 60}=59.5\]                                 Oxidation number of the metal \[=\frac{177}{59.5}=+\,3\]


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