question_answer

On the basis of the information available from the reaction \[\frac{4}{3}Al+{{O}_{2}}\to \frac{2}{3}A{{l}_{2}}{{O}_{3}},\Delta G=-827kJmo{{l}^{-1}}\] of \[{{O}_{2}}\], the minimum emf required to carry out an electrolysis of \[A{{l}_{2}}{{O}_{3}}\] is (F = 96500C \[mo{{l}^{-1}}\])  [CBSE PMT 2003]

A)                 8.56 V   

B)                 2.14 V

C)                 4.28 V   

D)                 6.42 V