A) 56
B) 84
C) 112
D) 168
Correct Answer: B
Solution :
\[F{{e}^{2+}}+2{{e}^{-}}\to Fe;\,\,{{E}_{Fe}}=\frac{56}{2}=28\] \[{{W}_{Fe}}={{E}_{Fe}}\] × Number of faraday \[=28\times 3=84\,\,gm\].You need to login to perform this action.
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