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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    The quantity of electricity needed to liberate 0.5 gram equivalent of an element is           [CPMT 1988; MP PMT 1997]

    A)                 48250 Faradays

    B)                 48250 Coulombs

    C)                 193000 Faradays             

    D)                 193000 Coulombs

    Correct Answer: B

    Solution :

               Electricity required            = No. of gm equivalent ´ 96500 coulombs                                 = 0.5 ´ 96500 = 48250 C.


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