A) 0.5 F
B) 0.1 F
C) 1.5 F
D) 96500 coulombs
Correct Answer: A
Solution :
\[N{{a}^{+}}+{{e}^{-}}\to Na\] Charge (in F) = moles of e? used = moles of Na deposited \[=\frac{11.5}{23}\ gm=0.5\]Faraday.You need to login to perform this action.
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