A) Platinum sulphate
B) Copper hydroxide
C) Copper sulphate
D) Sulphuric acid
Correct Answer: D
Solution :
During electrolysis of\[CuS{{O}_{4}}\].\[C{{u}^{2+}}\] gets discharged at cathode and \[O{{H}^{-}}\]at anode. Thus solution becomes acidic due to excess of \[{{H}^{+}}\] and \[SO_{4}^{2-}\] or \[{{H}_{2}}S{{O}_{4}}\].You need to login to perform this action.
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