A) 66 g
B) 1.32 g
C) 33 g
D) 99 g
Correct Answer: B
Solution :
At Andoe \[At\,\,Anode\,\,\,C{{l}^{-}}\to \frac{1}{2}C{{l}_{2}}+{{e}^{-}}\] \[{{E}_{C{{l}_{2}}}}=\frac{35.5\times 2}{2}=35.5\] \[{{W}_{C{{l}_{2}}}}=\frac{{{E}_{C{{l}_{2}}}}\times I\times t}{96500}\]\[=\frac{35.5\times 2\times 30\times 60}{96500}=1.32\,\,gm\].You need to login to perform this action.
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