A) 12.7 gm
B) 15.9 gm
C) 31.8 gm
D) 63.5 gm
Correct Answer: B
Solution :
\[\frac{\text{Weight}\,\,\text{of}\,\,Cu}{\text{Weight}\,\,\text{of}\,\,{{H}_{2}}}=\frac{\text{Eq}\text{.}\,\,\text{weight}\,\,\text{of}\,Cu}{\text{Eq}\text{.}\,\,\text{weight}\text{.}\,\,\text{of}\,\,H}\] \[\frac{\text{Weight}\,\,\text{of}\,\,Cu}{0.50}=\frac{63.6/2}{1}\] \[\text{Weight}\,\,\text{of}\,\,Cu=15.9\] gm.
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