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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    The amount of silver deposited by passing 241.25 coulomb of current through silver nitrate solution is    [MHCET 2003]

    A)                 2.7 g     

    B)                 2.7 mg

    C)                 0.27 g   

    D)                 0.54 g

    Correct Answer: C

    Solution :

               Given, Current = 241.25 columb                    1 coulomb current will deposite \[=1.118\times {{10}^{-3}}gm\ Ag\].                    \[\therefore \] 241.25 current will deposite =\[1.118\times {{10}^{-3}}\times 241.25\]                                 \[=0.27\ gm\] silver.


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