JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Faraday's law of electrolysis

  • question_answer
    An electric current is passed through silver nitrate solution using silver electrodes. 10.79 g of silver was found to be deposited on the cathode if the same amount of electricity is passed through copper sulphate solution using copper electrodes, the weight of copper deposited on the cathode is [Kerala PMT 2004]

    A)                 6.4 g     

    B)                 2.3 g

    C)                 12.8 g   

    D)                 1.6 g

    E)                 3.2 g

    Correct Answer: E

    Solution :

               Number of equivalents of silver formed = Number of equivalents of copper formed.                    In \[AgN{{O}_{3}},\ Ag\]is in +1 oxidation state.                    In \[CuS{{O}_{4}},\ Cu\]is in +2 oxidation state.                    Equivalent weight of Ag =\[\frac{108}{1}=108\]                    Equivalent weight of Cu  \[=\frac{63.6}{2}=31.8\]                    \[\frac{{{M}_{1}}}{{{M}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] ; \[\frac{10.79}{{{M}_{Cu}}}=\frac{108}{31.8}\]                                 \[{{M}_{Cu}}=\frac{10.79\times 31.8}{108}=3.2\ gm\].


You need to login to perform this action.
You will be redirected in 3 sec spinner