A) 115800 C
B) 5790 C
C) 28950 C
D) 57900 C
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+6{{H}^{+}}+6{{e}^{-}}\to \]\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}+2{{H}_{2}}O\] 1 mole = 123 gm nitrogen requires 6 mole electron e \[=6\times 96500\ coulomb\]charge \[\therefore \] 12.3 gm nitrobenzene will require \[=\frac{6\times 96500\times 12.3}{123}\] \[=6\times 9650\ =57900\ C.\]
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