A) 938.8 cal.
B) 1138.8 cal.
C) 1381.8 cal.
D) 1581.8 cal.
Correct Answer: C
Solution :
\[-\,W=+\,2.303\,nRT\,\]log \[\frac{{{p}_{1}}}{{{p}_{2}}}\] \[-\,W=2.303\times 1\times 2\times 300\]log \[\frac{10}{1}\] \[=1381.8\,cal.\]You need to login to perform this action.
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