A) \[\Delta H=\Delta U\]
B) \[\Delta H=\Delta U+3RT\]
C) \[\Delta H=\Delta U+RT\]
D) \[\Delta H=\Delta U-3RT\]
Correct Answer: D
Solution :
\[A(s)+3B(g)\to 4C(s)+D(l)\] \[\Delta ng=0-3=-3\]; \[\Delta H=\Delta E+\Delta ngRT\]\[[\because \,\,\Delta E=\Delta U]\] \[\therefore \Delta H=\Delta U+(-3)\,(RT)\] \[\Delta H=\Delta U-3\,(RT)\]; \[\Delta H=\Delta U-3RT\]You need to login to perform this action.
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