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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank First law of thermodynamics and Hess law

  • question_answer
    The work done during the expansion of a gas from a volume of \[4d{{m}^{3}}\] to \[6d{{m}^{3}}\] against a constant external pressure of \[3atm\] is (\[1L\,atm\,=101.32\,J\])             [CBSE PMT 2004]

    A)                 + 304 J  

    B)                 ?304 J

    C)                 ? 6 J      

    D)                 ?608 J

    Correct Answer: D

    Solution :

               \[W=-p\Delta V\];  \[W=-3\times (6-4)\]                    \[W=-6\times 101.32\] (\[\therefore \,1\,L\,atm\,=101.32\,J\])                                 \[W=-608\,J\]


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