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JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    Find the change in internal energy of the system when a system absorbs 2 kilocalorie of heat and at the same time does 500 joule  of work                                           [EAMCET 1984]

    A)            7900 J                                      

    B)            8200 J

    C)            5600 J                                      

    D)            6400 J

    Correct Answer: A

    Solution :

                       \[\Delta Q=2k\,cal=2\times {{10}^{3}}\times 4.2J\]\[=8400J\]and \[\Delta W=500J.\] Hence from \[\Delta Q=\Delta U+\Delta W,\] \[\Delta W=\Delta Q-\Delta U\] = 8400 ? 500 = 7900 J


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