A) Work done on the gas is \[0.5\times {{10}^{5}}J\]
B) Work done by gas is \[0.5\times {{10}^{5}}J\]
C) Work done on gas is \[{{10}^{5}}J\]
D) Work done by gas is \[{{10}^{5}}J\]
Correct Answer: A
Solution :
In first process using \[\Delta Q=\Delta U+\Delta W\] Þ \[8\times {{10}^{5}}=\Delta U+6.5\times {{10}^{5}}\]Þ \[\Delta U=1.5\times 10J\] Since final and initial states are same in both process So \[\Delta U\] will be same in both process For second process using \[\Delta Q=\Delta U+\Delta W\] Þ \[{{10}^{5}}=1.5\times {{10}^{5}}+\Delta W\]Þ\[\Delta W=-0.5\times {{10}^{5}}J\]You need to login to perform this action.
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